F(-4)=2x^2+5x+1

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Solution for F(-4)=2x^2+5x+1 equation: 



(-4)=2F^2+5F+1

We move all terms to the left:

(-4)-(2F^2+5F+1)=0

We add all the numbers together, and all the variables

-(2F^2+5F+1)-4=0

We get rid of parentheses

-2F^2-5F-1-4=0

We add all the numbers together, and all the variables

-2F^2-5F-5=0

a = -2; b = -5; c = -5;
Δ = b2-4ac
Δ = -52-4·(-2)·(-5)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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